Using u substitution, which of the following is equivalent to this integral?

lude1
Messages
34
Reaction score
0

Homework Statement



Using the u substutituion u = 2x + 1, ∫(2x + 1)1/2dx (when x goes from 0 to 2) is equivalent to?

Answer: (1/2)*∫(u)1/2du (when x goes from 1 to 5)


Homework Equations





The Attempt at a Solution



If u is 2x + 1, then du = 2dx. Thus, I get

(1/2)*∫(u)1/2du (when x goes from 0 to 2)​

The only problem is where did the x goes from 1 to 5 come from? Did I do something wrong, or is the AP packet wrong?
 
Physics news on Phys.org
For a question like this, when you use substitution to solve a definite integral and have it in a form with u in it, you need to have the two limits in terms of u as well, not x.

So in this example, the limits are 0 to 2 and you know that u = 2x + 1. Just substitute in x = 0 and x = 2, and it gives you the new limits of 1 and 5.
 
Last edited:
Oh, yes, you are right. I forgot that in order for my answer to be right, it had to be (1/2)*∫(2x + 1)1/2du (when x goes from 0 to 2).

Thanks!
 
lude1 said:
Oh, yes, you are right. I forgot that in order for my answer to be right, it had to be (1/2)*∫(2x + 1)1/2du (when x goes from 0 to 2).

Thanks!
That should be (1/2)*∫(2x + 1)1/2dx.

It's not necessary to change the limits of integration when you do a substitution. You can work with the indefinite integral, make the substitution, get your antiderivative, undo your substitution, and then evaluate your antiderivative at the original limits.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
12
Views
2K
Replies
21
Views
2K
Replies
11
Views
2K
Replies
2
Views
1K
Replies
15
Views
2K
Replies
96
Views
4K
Replies
27
Views
2K
Replies
3
Views
2K
Back
Top