Calculating the Net Force of Bruce Nuclear Development

AI Thread Summary
The discussion focuses on calculating the net force acting on the Bruce Nuclear Development's vacuum building, which is a CANDU reactor. Participants clarify that the correct approach involves calculating the surface areas of both the inside and outside of the cylindrical structure, rather than simply adding the pressures. The external pressure is 90 kPa, while the internal pressure is 10.3 kPa, indicating a pressure difference that needs to be factored in. The net force is determined by applying the formula F = P x A, using the respective areas and pressures. Proper calculations will yield the net force acting on the building, emphasizing the importance of accurate area measurements.
mr.toronto
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Homework Statement


The Bruce Nuclear Development is a CANDU style reactor. This means that it has a "vaccum building" to "suck" (the contents of a malfunction reactor to a safer place. Refer to the engineering "specs" for the needed information to calculate the net force of the atmposhere acting on the building.

Dimensions of building- 51.m tall .914m thick and 52.1m diameter
Pressure- 90kpa outside of building and 10.3 kpa inside of the build

Homework Equations


mother formula-P= F/A
F= PxA


The Attempt at a Solution


so I'm guessing you add the to pressures you have so it would be 100.3 kpa

surface are of building-51mx52.1mx.914m=2 428.5 m squared

2428.5m x 100.3kpa=
2428.5 x 100 000=242 858 94 0N
 
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Well, if you were finding the pressure difference, you'd need to subtract, not add. However it's not as simple as that since the internal area and external area of the building are not the same due to the thickness of the walls.

It sounds like this building is a cylinder, but you've taken the measurements to be the length/width/depth and calculated what the volume would be in this case.

Have a think about how to calculate the area of the inside and outside of the building. Then use the respective pressures to calculate the forces on the inside and outside. After that, it's just a subraction.
 
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