Validating Stokes' Theorem Formula for Triangular Surface on y-z Plane?

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Homework Statement


Show that both sides of the Stoke's Theorem formula are valid for the function F= using the triangular surface on the y-z plane with corners at the origin, (0,2,0) and (0,0,2).

Homework Equations


Stokes Theorem equation( not sure how to write it out here) [/B]

The Attempt at a Solution


Took the curl of V, ended up with <-2y,-3z,-x> but when I go to integrate do I set x=0 and then dx=0 as well? So then, with y=2-z , bounds on the integrals are 0-2 and 0-(2-z) so (INT)(INT)(-3z)dydx with the bounds? But when I do this I end up with -4 ... Not sure where I am going wrong and I don't know how to prove the other side of the equation. Any help would be greatly appreciated.
 
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JB91 said:
1. The problem statement, all
and given/known data

Show that both sides of the Stoke's Theorem formula are valid for the function F=
You left out the function so we can't answer your question!
using the triangular surface on the y-z plane with corners at the origin, (0,2,0) and (0,0,2).

Homework Equations


Stokes Theorem equation( not sure how to write it out here) [/B]

The Attempt at a Solution


Took the curl of V, ended up with <-2y,-3z,-x> but when I go to integrate do I set x=0 and then dx=0 as well? So then, with y=2-z , bounds on the integrals are 0-2 and 0-(2-z) so (INT)(INT)(-3z)dydx with the bounds? But when I do this I end up with -4 ... Not sure where I am going wrong and I don't know how to prove the other side of the equation. Any help would be greatly appreciated.
 
Duplicate thread to https://www.physicsforums.com/threads/stokes-theorem.806286
 
Last edited by a moderator:
The name is "Stokes", not "Stoke". So it should be "Stokes' theorem".
 
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