Variation of masses in lead-acid battery due to H2SO4 mass variation

AI Thread Summary
In a lead-acid battery's discharge mode, a decrease of 294g (3 moles) of sulfuric acid results in the formation of 3 moles of lead sulfate (PbSO4) and 3 moles of water (H2O). The overall reaction indicates that the mass of lead (Pb) increases by 1.5 moles while the mass of lead dioxide (PbO2) decreases by 1.5 moles. This mass variation occurs due to the consumption of sulfuric acid and the corresponding electrochemical reactions. The initial confusion regarding the mass changes was clarified, confirming the provided answer was correct. Understanding these relationships is crucial for analyzing lead-acid battery behavior during discharge.
libelec
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Homework Statement



In discharge mode, calculate the variation in mass of the compounds of a lead-acid battery if the sufuric acid mass decreases by 294g (3 moles).

Homework Equations



The semirreactions:

Pb \to P{b^{2 + }} + 2{e^ - }
4{H^ + } + Pb{O_2} + 2{e^ - } \to P{b^{2 + }} + 2{H_2}O

The Attempt at a Solution



The only thing I could deduce was that if the H2SO4 decreases in 3 moles, then this means that 3 moles of PbSO4 were formed, along with 3 moles of H2O (since the relation is 1 mole of each of the former formed for each mole of H2SO4 consumed).

But I can't figure out what would happen to the Pb or the PbO2.

I have the answers: Pb increases in 1,5 moles and PbO2 decreases in 1,5 moles.

Any ideas?

Thanks
 
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Try with overall reaction equation.

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methods
 
But the overall reaction:

Pb + Pb{O_2} + 2{H_2}S{O_4} \to 2PbS{O_4} + 2{H_2}O

doesn't tell me why the Pb mass increases and the PbO2 mass decreases.
 
Perhaps that means that the answer you were given is incorrect?

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methods
 
Yes, such was the case. Thank you.
 
libelec said:
Yes, such was the case. Thank you.

Not that I am surprised :wink:

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