Vector 2B - Vector A (graphical method)

AI Thread Summary
Vector A is 4.00 units at 40 degrees below the x-axis, while Vector B is 3.00 units at 25 degrees below the negative x-axis. The task is to calculate Vector 2B - Vector A using a graphical method. Confusion arises regarding the components of the vectors and how to properly apply vector subtraction. After several attempts, one participant calculated the result as 2B - A = -0.8i - 0.6j, with a magnitude of 1, indicating ongoing uncertainty about the correct approach.
s31t8n8
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Homework Statement



Vector A is 4.00 units and 40* below x-axis. Vector B is 3.00 units and 25* below -x-axis. Use the graphical method (only ruler and protractor) to find Vector 2B - Vector A. I have to find the magnitude and direction.

When I did it I got 8.5 and East, but I'm not sure if I did it right. When they say 4.00 and 3.00 units, is that the ax component of the vector? That's the way I did it. I drew out the vector then measured 3 and 4 units on the ax comp. of both vectors, then measured from that point down to the vector and got the ay component. Then I just solved for the magnitude.

thanks
 
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s31t8n8 said:

Homework Statement



Vector A is 4.00 units and 40* below x-axis. Vector B is 3.00 units and 25* below -x-axis. Use the graphical method (only ruler and protractor) to find Vector 2B - Vector A. I have to find the magnitude and direction.

When I did it I got 8.5 and East, but I'm not sure if I did it right. When they say 4.00 and 3.00 units, is that the ax component of the vector? That's the way I did it. I drew out the vector then measured 3 and 4 units on the ax comp. of both vectors, then measured from that point down to the vector and got the ay component. Then I just solved for the magnitude.

thanks

The vector length is 4 at an angle of 40 degrees down below positive X axis and the other vector is 3 long pointing down from the negative x-axis. (The other direction of x)

But they say 2*B which makes that vector 6 long.
 
LowlyPion said:
The vector length is 4 at an angle of 40 degrees down below positive X axis and the other vector is 3 long pointing down from the negative x-axis. (The other direction of x)

But they say 2*B which makes that vector 6 long.

ok i just redrew it and now I am lost. I am getting confused about what theyre asking
 
s31t8n8 said:
ok i just redrew it and now I am lost. I am getting confused about what theyre asking

You've drawn the two vectors - doubling B?

Then reverse Vector A - same length - opposite direction.

They say 2*B - A right. This is vector subtraction. But you do that by "adding" the negative of the Vector A.

Now add these two vectors together.
 
ok i did it again and I am sure i got it wrong again but i got
2*B-A= -.8i-.6j
magnitude = 1
 
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