1. Vector A has a magnitude of 14 m and makes an angle of 26o with the positive x axis. Vector B also has a magnitude of 13 m and is directed along the negative x axis. Enter your answers in distance then angle(in degrees). 2. Find A + B Find A - B 3. 14cos(26)=12.6 x component for A 14sin(26)=6.14 y component for A -13 x component for B 0 y component for B A+B sqrt( (Ax+Bx)^2 + (Ay+By)^2 ) sqrt( (12.6-13)^2 + (6.14)^2 ) A+B=6.16 tan-1(y/x) tan-1(6.14/-.4)=-86.3* I haven't attempted A-B yet. Tell me where I'm going wrong. Any help is appreciated.
in the arctan equation .4 should be -.4, also why are you using 6.15 when the only vertical component is 6.14?