1. Feb 8, 2011

### steve7

1. Vector A has a magnitude of 14 m and makes an angle of 26o with the positive x axis. Vector B also has a magnitude of 13 m and is directed along the negative x axis. Enter your answers in distance then angle(in degrees).

2. Find A + B
Find A - B

3. 14cos(26)=12.6 x component for A
14sin(26)=6.14 y component for A

-13 x component for B
0 y component for B

A+B
sqrt( (Ax+Bx)^2 + (Ay+By)^2 )

sqrt( (12.6-13)^2 + (6.14)^2 )

A+B=6.16

tan-1(y/x)
tan-1(6.14/-.4)=-86.3*

I haven't attempted A-B yet.
Tell me where I'm going wrong. Any help is appreciated.

Last edited: Feb 8, 2011
2. Feb 8, 2011

### Asphyxiated

in the arctan equation .4 should be -.4, also why are you using 6.15 when the only vertical component is 6.14?

3. Feb 8, 2011

### steve7

it was a typo. I corrected them.

thanks