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Vector addition and subtraction

  1. Feb 8, 2011 #1
    1. Vector A has a magnitude of 14 m and makes an angle of 26o with the positive x axis. Vector B also has a magnitude of 13 m and is directed along the negative x axis. Enter your answers in distance then angle(in degrees).



    2. Find A + B
    Find A - B




    3. 14cos(26)=12.6 x component for A
    14sin(26)=6.14 y component for A

    -13 x component for B
    0 y component for B

    A+B
    sqrt( (Ax+Bx)^2 + (Ay+By)^2 )

    sqrt( (12.6-13)^2 + (6.14)^2 )

    A+B=6.16

    tan-1(y/x)
    tan-1(6.14/-.4)=-86.3*

    I haven't attempted A-B yet.
    Tell me where I'm going wrong. Any help is appreciated.
     
    Last edited: Feb 8, 2011
  2. jcsd
  3. Feb 8, 2011 #2
    in the arctan equation .4 should be -.4, also why are you using 6.15 when the only vertical component is 6.14?
     
  4. Feb 8, 2011 #3
    it was a typo. I corrected them.

    thanks
     
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