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**1. Vector A has a magnitude of 14 m and makes an angle of 26o with the positive x axis. Vector B also has a magnitude of 13 m and is directed along the negative x axis. Enter your answers in distance then angle(in degrees).**

**2. Find A + B**

Find A - B

Find A - B

**3. 14cos(26)=12.6 x component for A**

14sin(26)=6.14 y component for A

-13 x component for B

0 y component for B

A+B

sqrt( (Ax+Bx)^2 + (Ay+By)^2 )

sqrt( (12.6-13)^2 + (6.14)^2 )

A+B=6.16

tan-1(y/x)

tan-1(6.14/-.4)=-86.3*

I haven't attempted A-B yet.

Tell me where I'm going wrong. Any help is appreciated.

14sin(26)=6.14 y component for A

-13 x component for B

0 y component for B

A+B

sqrt( (Ax+Bx)^2 + (Ay+By)^2 )

sqrt( (12.6-13)^2 + (6.14)^2 )

A+B=6.16

tan-1(y/x)

tan-1(6.14/-.4)=-86.3*

I haven't attempted A-B yet.

Tell me where I'm going wrong. Any help is appreciated.

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