(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 5.0 Kg block at rest on a frictionless surface is acted on by forces F1= 5.5N and F2= 3.5N, as illustrated in the figure.

A)What additional force (in unit vector notation) is required to keep the block at rest?

B)What additional force (in unit vector notation) is required to accelerate the block at a rate of 2.25 m/s^2

Force 1: 3.5N at 37 degrees above +X axis

Force 2: 5.5N at 30 degrees below +X axis

2. Relevant equations

F=m*a

S O H C A H T O A

3. The attempt at a solution

The first step I took was to use trig functions to find the X and Y components of F1 and F2. I came up with the following:

F1X=3.5cos37=2.80N

F1Y=3.5sin37=2.12

F2X=5.5cos30=4.76N

F2Y=5.5cos30=-2.75N

Adding the X and Y components from each vector together I came to this answer for "F3" which would represent the two vectors.

F3X=7.56N F3Y=-0.63N

Then used Pythagorean theorem to find the hypotenuse (the magnitude of the new force)

which was:

7.56^2 + -0.63^2=X^2

X=7.53N

To find the angle of the new force I used:

tan^-1(-0.63 / 7.56) = -4.76 degrees

This equation gave me essentially the opposite of the angle I was looking for (if I'm thinking correctly about this problem) making the magnitude of the force to "keep the block at rest" would be -7.52N at 4.76 degrees above the -X Axis.

This answer was turned in and received a 6/10 possible points. I need help determining where I went wrong, and how I can fix it so I can turn the problem back in for a small return...not to mention it's bothering me that I don't know what I did wrong!

Thanks in advance,

Ian

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# Homework Help: Vector Addition + Extras

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