Vector addition - Vector Spaces

depre87
Messages
8
Reaction score
0

Homework Statement


Show if V is a vector space ([a,b,c]|ab>=0). I'm trying to test whether it is closed under
vector addition.




Homework Equations


v=[a1,b1,c1] w=[a2,b2,c2], v and w satisfy ab>=0
a1b1>=0, a2b2>=0
show (a1+a2)(b1+b2)>=0



The Attempt at a Solution


Got to a1b1 + a2b2 +a1b2 + a2b1 after expanding the above equation. Know a1b1 and a2b2 both >=0 however what do I do with the a1b2 and a2b1? I've attempted trying to factor them into a1b1 and have gotten a1b1[(b2/b1)+(a2/a1)] and know a1b1 >=0 however not sure what to do with the terms in the bracket to further prove whether or not it is closed under vector addition.
 
Physics news on Phys.org
Hi depre87! :smile:

Have you tried searching a counterexample?
 
I just had a look and I don't understand it enough to apply it to my question, could you enlighten me? thanks for the suggestion though.
 
Just try some numerical values of v and w and see if you can come up with a counterexample...
 
one way you could do it is to picture a & b in a 2D plane, the allowable areas are a&b both +ve, or both -ve. Now try and think of a vector addition that will take you outside of teh allowable areas (the a&b axes may be a good start)
 
Look at scalar multiplication rather than addition. If v is such a vector, what is (-1)v?

Or, similarly, every vector must have an additive inverse.
 
Last edited by a moderator:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top