Vector Cross Product Homework: Find a×(a-2b+c)

AI Thread Summary
To solve the vector cross product a×(a-2b+c), start by using the distributive property of the cross product. Given a×b = -i - j + 3k and c×a = 2i - 3j + k, you can simplify the expression without needing the individual components of vectors a, b, and c. It is confirmed that a×a equals zero, which is a key point in the calculation. The focus should remain on the provided cross products rather than deriving the components of the vectors. Following these steps will lead to the correct solution.
Cpt Qwark
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Homework Statement


Given a×b=-i-j+3k and c×a=2i-3j+k, find a×(a-2b+c)

Homework Equations


Cross product (DONE WITHOUT MATRICES).

The Attempt at a Solution


a[/B]×b=c=-(b×a)is all I'm getting to at this point
 
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Cpt Qwark said:

Homework Statement


Given a×b=-i-j+3k and c×a=2i-3j+k, find a×(a-2b+c)

Homework Equations


Cross product (DONE WITHOUT MATRICES).

The Attempt at a Solution


a[/B]×b=c=-(b×a)is all I'm getting to at this point
Simply distribute the cross-product.

##\vec{P}\times(\vec{Q}+\vec{R})=\vec{P}\times\vec{Q}+\vec{P}\times\vec{R}##
 
Thanks,
so would I have to find the components of a, b, and c?
 
Cpt Qwark said:
Thanks,
so would I have to find the components of a, b, and c?
No. Not at all.

What is a×a ?
 
Cpt Qwark said:
Thanks,
so would I have to find the components of a, b, and c?

No, you only need the components of axb and axc. Follow SammyS's suggestion.
 
Ok thanks guys I got it
 
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