Vector Cross Product: Perpendicular Vectors lV_1 x V_2l

In summary, the magnitude of the cross product between two perpendicular vectors V_1 and V_2 is equal to the product of the magnitudes of the vectors and the cosine of the angle between them. This only applies in 3 dimensional space and there is a sign ambiguity. There was a mistake in the original calculation, as the correct formula is |V_1| * |V_2| * sin(a).
  • #1
horsegirl09
16
0
If vectors V_1 and V_2 are perpendicular, lV_1 x V_2l =? I know that if they are parallel for vector cross product, they equal 0.
 
Physics news on Phys.org
  • #2
horsegirl09 said:
If vectors V_1 and V_2 are perpendicular, lV_1 x V_2l =? I know that if they are parallel for vector cross product, they equal 0.
The cross product is a vector perpendicular to V_1 and V_2. Also V_1 and V_2 don't have to be perpendicular to each other, only not parallel.

Note that this only makes sense in 3 dimensional space.

Further note: the magnitude is |V_1|x|V_2|cos(a), where a is the angle between the vectors. There is a sign ambiguity.
 
Last edited:
  • #3
Isn't it |V_1|*|V_2|*sin(a)?
 
  • #4
ehj said:
Isn't it |V_1|*|V_2|*sin(a)?

You're right - my bad.
 
Back
Top