- #1
Lamnia
- 7
- 0
The minute hand on a watch is 2.0 cm in length. What is the displacement vector of the tip of the minute hand from 8:00am to 8:20am. Express the vector in x and y components.
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I'm beginning to be a little frustrated with what I thought was a simple vector addition problem.
Here's my approach:
at 8 the y component is 2cm, and the x component is zero
as the minute hand moves in 5 minute intervals around the clock, it covers intervals of 30 degrees. Therefore at 8:20, the y component should be -(2cm*sin30) and the x component should be 2cm*cos30.
Upon addition of the components we would have x = sqrt 3 and y = 2-1 =1
However, I've submitted these answers, and they are incorrect.
Can someone please indicate where I went wrong so that I can recalculate and resubmit this homework problem? Thank you :)
---------------------------------------------------------------------------------------------------
I'm beginning to be a little frustrated with what I thought was a simple vector addition problem.
Here's my approach:
at 8 the y component is 2cm, and the x component is zero
as the minute hand moves in 5 minute intervals around the clock, it covers intervals of 30 degrees. Therefore at 8:20, the y component should be -(2cm*sin30) and the x component should be 2cm*cos30.
Upon addition of the components we would have x = sqrt 3 and y = 2-1 =1
However, I've submitted these answers, and they are incorrect.
Can someone please indicate where I went wrong so that I can recalculate and resubmit this homework problem? Thank you :)