Vector Displacement: Tip of Minute Hand 8:00-8:20 & 8:00-9:00

AI Thread Summary
The discussion focuses on calculating the displacement vector of the tip of a minute hand on a watch, specifically from 8:00 to 8:20 and from 8:00 to 9:00. The minute hand is 2.0 cm long, and participants are struggling with the correct displacement values, often arriving at 1.8 or 2.8 without satisfying the program's requirements for significant figures. The key to solving the problem lies in determining both the magnitude and direction of the movement over the specified time intervals. Clarification is needed on how to accurately calculate and express the displacement vector to meet the program's criteria. Understanding vector displacement is essential for correctly completing the assignment.
tgras141
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Homework Statement


The minute hand on a watch is 2.0cm in length. What is the displacement vector of the tip of the minute hand:
a. from 8:00 to 8:20
b. From 8:00 to 9:00


Homework Equations




The Attempt at a Solution


I keep getting that the displacement is 1.8,2.8, but the program we have to put it in for class it keeps frickin saying "Almost... blah blah blah some crap about checkin sig figs.
 
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I keep getting that the displacement is 1.8,2.8...
How are you arriving at these results?
 
A displacement vector consists of a magnitude and direction.

In other words, after 20 minutes, how far did the tip of the minute hand move and in what direction?
 

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