Vector problem A (1 Viewer)

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1a) F1 = 210 Newtons, 43.0 degrees Wof N

I drew the picture
F1x = 210 cos 43 = 154 N
F1y = 210 sin 43 = 143 N

2a) F2 = 76.0 Newtons, 23.7 degrees Sof E
same set up[ as above

F2x = 70 N
f2y = 31 N or should this be negitive
 

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I assume the problem is to find the x & y components of the given forces.

Originally posted by cowgiljl
1a) F1 = 210 Newtons, 43.0 degrees Wof N

I drew the picture
F1x = 210 cos 43 = 154 N
F1y = 210 sin 43 = 143 N
If the 43 degrees is as you say (W of N), then you have mixed up the x & y components. (Careful with the angles.) Also, the x component would be negative.
2a) F2 = 76.0 Newtons, 23.7 degrees Sof E
same set up[ as above

F2x = 70 N
f2y = 31 N or should this be negitive
This time you didn't mix up the angles. Yes, the y-component is negative.
 

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