Vector Problem Homework: Finding Components and Resultant of Three Forces

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The discussion revolves around calculating the components and resultant of three forces applied to a particle. The forces are defined as F1 along the x-axis, F2 at 30 degrees from the positive y-axis, and F3 at 30 degrees from the negative y-axis, each with a magnitude of 5.00 N. The user calculated the components of F2 and F3 and found them to be F2 (-2.5, 4.33) and F3 (-2.5, -4.33), while F1 is (5, 0). Upon summing these components, the resultant R was determined to be zero, confirming that the calculations were correct and indicating that the forces are in equilibrium.
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Homework Statement


There are three forces, each of magnitude 5.00 N applied to a particle at O in the directions shown in Fig. 1. List the components of the individual forces F1, F2, and F3. Obtain the x and y components of the resultant of the three forces, R = F1 + F2 + F3 and the magnitude of R and its direction by giving the angle to one of the axes.

F1 vector is right on the x-axis and its direction is east.
F2 vector is 30 degrees from +y. It is between north and west.
F3 vector is 30 degrees from -y. It is between south and west.

Homework Equations


The Attempt at a Solution


For the F3 vector, I did sine 30 = x/5 and I got 2.5. Then I used cosine and I got 4.33 for the other side. I did the same process for the F2 vector.

So my components were:
F3 (-2.5, -4.33)
F2 (-2.5, 4.33)
F1 (5, 0)

I add the component up to get R and I get 0 for the components and for the vector of R. Did I do something wrong? Or is this correct?
 
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Help anyone?
 
Welcome to PF!

Hi Amuro! Welcome to PF! :smile:
Amuro said:
I add the component up to get R and I get 0 for the components and for the vector of R. Did I do something wrong? Or is this correct?

No, that looks correct … the magnitude is 0, and the angle is irrelevant. :wink:
 


tiny-tim said:
Hi Amuro! Welcome to PF! :smile:


No, that looks correct … the magnitude is 0, and the angle is irrelevant. :wink:

Thank you.
 
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