My main issue is trying to understand the question being asked (is it asking for the magnitude of the resultant vector for speed?) 1. The problem statement, all variables and given/known data Particle 1 is moving on the x-axis with an acceleration of 5.00 m/s^2 in the positive x- direction. Particle 2 is moving on the y- axis with an acceleration of 6.00 m/s^2 in the negative y-direction. Both particles were at rest at the origin at t = 0 s. Find the speed of particle 1 with respect to particle 2 at 4.00 s. Answer in m/s. 2. Relevant equations I know that this is a problem involving constant acceleration so: [tex]v = v_0 + a t[/tex] One for the x direction and one for the y direction. 3. The attempt at a solution So V0x and V0y are both 0. Then, Vxf=(5m/s^2)(4s)=20 m/s and Vyf=(-6m/s^2)(4s)=-24 m/s. Now the problem is whether the problem wants me to find the resultant speed (the wording is somewhat confusing for me). If so, then sqrt(20^2+(-24)^2)) or about 31.2 m/s. If not, I have no idea. I'd appreciate if someone could let me know if I'm on the right track. Thanks!