Vector Proof: x x v = u x v = x x u

AI Thread Summary
The discussion revolves around proving the equation x x v = u x v = x x u given that x + v = u. Participants express confusion about how to approach the proof, with one suggesting the use of the associative rule and another emphasizing the importance of vector direction. A key insight is substituting u into the equation, leading to simplifications that show x x v can be expressed in terms of u x v. Ultimately, the conversation highlights the need to understand properties of the cross product and vector relationships to solve the problem. The exchange concludes with confirmation of the correctness of the approach taken.
Jbreezy
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Homework Statement



If x + v = u
Prove x x v = u x v = x x u

The Attempt at a Solution



I don't even know where to start with this. I thought that magnitude of the resultant vector would have to be equal. So I started messing with each to see if I could find a pattern.

x x v = | x|| v| sin θ

This is a crap approach I can't find anything. Please give me a hint not the answer. I just can't seem to draw the information in my text together to give myself enough to show this. Thank you.
 
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Just use your definition of u in the equations, and simplify with known properties of the cross product.
It does not help to consider the magnitude of the vectors, as their "direction" has to fit, too.
 
Hi Jbreezy! :smile:

Are you allowed to use the associative rule, a x (b + c) = a x b + a x c ?

Or do you have to use coordinates?
 
I guess you are allowed to use whatever. I don't understand this problem at all.
 
ok, then what is x x (u - v) ? :wink:
 
0 vector? This is not anywhere in my eq. though. In terms of the original.
 
This was a good problem to make me feel like a monkey with a stick.

so, If x + v = u
Prove x x v = u x v = x x u

Sub in u.

x x v = (x + v ) x v = x x(x + v)

So when you distribute.

X x V = X x V + V x V = X x X + X x v

So, V x V = 0 , X x X = 0
So
X x V = X x V = X x V
Thanks
 
Hi Jbreezy! :smile:

(just got up :zzz:)

Yes, that's correct. :smile:

But it's a bit long-winded …

you could have done x x v = (x + v ) x v (because v x v = 0)

= u x v,​

or x x v - u x v = … (you finish it :wink:)
 
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