Vectors: Find w such that dv/ds = w x v

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Homework Statement



T (tangent), B (binormal), N (normal) are an orthogonal triad of unit vectors of a curve in R3.Given:
  • dT/ds = kN
  • dN/ds = -kT + tB
  • dB/ds = -tN

Find vector w so that these equations may be written in the form:

dv/ds = w x v, where v = T + N + B

Homework Equations



Given above!

The Attempt at a Solution



I tried splitting v (T + N + B) into its components, as well as w, and putting them into a matrix to find the determinant (for the cross product).

The matrix consists of <i, j, k>, w = <w1, w2, w3>, and v = <(T1 + N1 + B1), (T2 + N2 + B2), (T3 + N3 + B3)>.

However, taking the determinant/cross product gives mismatching components (ie. j and k components supposedly add up to an i component). I'm not too sure where to go from here :(
Note: This is for a Multivariate Calculus course!
 
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YayMathYay said:

Homework Statement



T (tangent), B (binormal), N (normal) are an orthogonal triad of unit vectors of a curve in R3.Given:
  • dT/ds = kN
  • dN/ds = -kT + tB
  • dB/ds = -tN

Find vector w so that these equations may be written in the form:

dv/ds = w x v, where v = T + N + B

Homework Equations



Given above!

The Attempt at a Solution



I tried splitting v (T + N + B) into its components, as well as w, and putting them into a matrix to find the determinant (for the cross product).

The matrix consists of <i, j, k>, w = <w1, w2, w3>, and v = <(T1 + N1 + B1), (T2 + N2 + B2), (T3 + N3 + B3)>.

However, taking the determinant/cross product gives mismatching components (ie. j and k components supposedly add up to an i component). I'm not too sure where to go from here :(
Note: This is for a Multivariate Calculus course!

Hi YayMathYay, welcome to PF! :smile:

There's a much easier way to do this than by looking at the Cartesian components of the vectors.

Hint: What is \mathbf{v}\times ( \mathbf{w} \times \mathbf{v} )?
 
gabbagabbahey said:
Hi YayMathYay, welcome to PF! :smile:

There's a much easier way to do this than by looking at the Cartesian components of the vectors.

Hint: What is \mathbf{v}\times ( \mathbf{w} \times \mathbf{v} )?

First of all, thanks for the welcome! :)

I know the hint you gave me means \left(\mathbf{v} \bullet \mathbf{v}\right)\mathbf{w} - \left(\mathbf{v} \bullet \mathbf{w}\right)\mathbf{v}. I've tried this method before, but I wasn't too sure where to go from here..
 
YayMathYay said:
First of all, thanks for the welcome! :)

I know the hint you gave me means \left(\mathbf{v} \bullet \mathbf{v}\right)\mathbf{w} - \left(\mathbf{v} \bullet \mathbf{w}\right)\mathbf{v}. I've tried this method before, but I wasn't too sure where to go from here..

For starters, what is \mathbf{v} \cdot \mathbf{v} ? Next since \mathbf{T}, \mathbf{B} & \mathbf{N} are an orthogonal triad in \mathbb{R}^3, they span \mathbb{R}^3, and so any vector can be decomposed into a linear combination of those unit vectors. So, why not write \mathbf{w} = w_{T}\mathbf{T} + w_{N}\mathbf{N} + w_{B}\mathbf{B}... what does that make \mathbf{w} ( \mathbf{v} \cdot \mathbf{v} ) - \mathbf{v} ( \mathbf{w} \cdot \mathbf{v} )?
 
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