Vectors Thinking Question: Proving Perpendicularity using the Cosine Law

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Homework Statement



a) Write the cosine law using a vector operation.
b) If |vector a - vector b| = |vector a + vector b|, prove that a is perpendicular to b using the formula you found in a).

The Attempt at a Solution



The red period represents the dot product

a) magnitude c = SQUAREROOT (a.a + b.b - 2(a.b) )

b) magnitude c = SQUAREROOT (a.a + b.b - 2(a.b) )

= SQUAREROOT ( a2 + b2 - 2( |a||b|cos 90 )
= SQUAREROOT ( a2 + b2 )

And this is the Pythagorean theorem, which only applies for right angle triangles, so if mag. C is SQUARERT (a2+b2), then a and b are perpendicular.

DId I do this correctly?

I didn't know how to include |vector a - vector b| = |vector a + vector b| into the equation and it only asked to prove it using the formula that I found...
 
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DespicableMe said:

Homework Statement



a) Write the cosine law using a vector operation.
b) If |vector a - vector b| = |vector a + vector b|, prove that a is perpendicular to b using the formula you found in a).

The Attempt at a Solution



The red period represents the dot product

a) magnitude c = SQUAREROOT (a.a + b.b - 2(a.b) )

b) magnitude c = SQUAREROOT (a.a + b.b - 2(a.b) )

= SQUAREROOT ( a2 + b2 - 2( |a||b|cos 90 )
= SQUAREROOT ( a2 + b2 )

And this is the Pythagorean theorem, which only applies for right angle triangles, so if mag. C is SQUARERT (a2+b2), then a and b are perpendicular.

DId I do this correctly?

I didn't know how to include |vector a - vector b| = |vector a + vector b| into the equation and it only asked to prove it using the formula that I found...

The b part isn't correct. You need to start by assuming that |a - b| = |a + b|, and showing that it follows that a and b are perpendicular.

You could start by assigning coordinates to a and b, such as a = <a1, a2> and b = <b1, b2>.
 
Mark44 said:
The b part isn't correct. You need to start by assuming that |a - b| = |a + b|, and showing that it follows that a and b are perpendicular.

You could start by assigning coordinates to a and b, such as a = <a1, a2> and b = <b1, b2>.

I'm still kind of...
What can I do with the coordinates?

At one point, I did draw vector diagrams to show|a - b| = |a + b| but other than that, I didn't know how to use that in the equation.
 
Start by writing out the magnitudes using the definition of magnitude. Of course, it would be easier if you squared both sides first.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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