Vectory Geometry, problem involving spheres

  • Thread starter Thread starter josephcollins
  • Start date Start date
  • Tags Tags
    Geometry Spheres
AI Thread Summary
To determine if triangle PQR is right-angled, the dot product of vectors PQ and QR is calculated, confirming they are perpendicular. The next step involves finding the equation of the smallest sphere that passes through points P, Q, and R. The center of the sphere must be equidistant from all three points, leading to a system of equations based on their coordinates. To minimize the sphere's radius, the center should lie in the plane formed by the points, allowing for a circle to be established as the equator of the sphere. This approach effectively combines geometric properties with algebraic equations to solve the problem.
josephcollins
Messages
59
Reaction score
0
Hi ppl, ne1 know how to approach this one?

Given P(1,4,-1), Q(1,2,-1) and R (3,2,-2), show that PQR is right angled and hence find the equation of the smallest sphere S which passes through P,Q and R.

Okay, I got the right angle by showing PQ and QR to be perpendicular with the dot product as zero.
With the equation of the sphere, I'm not sure how to start this, could someone just point me in the correct direction,
Thanks,
Joe
 
Physics news on Phys.org
josephcollins said:
Hi ppl, ne1 know how to approach this one?

Given P(1,4,-1), Q(1,2,-1) and R (3,2,-2), show that PQR is right angled and hence find the equation of the smallest sphere S which passes through P,Q and R.

Okay, I got the right angle by showing PQ and QR to be perpendicular with the dot product as zero.
With the equation of the sphere, I'm not sure how to start this, could someone just point me in the correct direction,
Thanks,
Joe

You know that the center of the sphere is the same distance from all the points.

So: sqr((x - 1)^2 + (y - 4)^2 + (z - -1)^2) = sqr((x -1 ...
 
Alkatran's answer will give you two equations in three unknowns, since it holds for all spheres. To get the smallest sphere, you need the condition that the center lies in the plane determined by the three points. A way of approaching it, is to work in that plane, and get a circle passing through the three points. The sphere you want will have that circle as the equator.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top