Velocity and acceleration of an army tank

AI Thread Summary
An army tank fires a shell horizontally, which strikes the ground 6000 m away with a vertical striking velocity of 200 m/s. The gravitational acceleration is given as 10 m/s². The discussion highlights a mistake in mixing vertical and horizontal components in the equations used for calculating time of flight. The correct approach requires using vertical displacement and velocity in the relevant equations. The key takeaway is to keep vertical and horizontal calculations separate when analyzing projectile motion.
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Homework Statement



An army tank on a mountainside fires its gun horizontally. The shell strikes the ground at a horizontal distance of 6000 m away from the tank. As the vertical component of the shell’s striking velocity is vy=200 m/s, how soon after it is fired does the shell strike the ground? (g=10 m/s2)

Homework Equations


v^2=2ax (1)
x=at^2/2 (2)

The Attempt at a Solution


40000=2*a*6000
then find t with (2) but why is it the component vy?
 
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ad848 said:

Homework Statement



An army tank on a mountainside fires its gun horizontally. The shell strikes the ground at a horizontal distance of 6000 m away from the tank. As the vertical component of the shell’s striking velocity is vy=200 m/s, how soon after it is fired does the shell strike the ground? (g=10 m/s2)

Homework Equations


v^2=2ax (1)
x=at^2/2 (2)

The Attempt at a Solution


40000=2*a*6000
then find t with (2) but why is it the component vy?
It isn't. If you use an equation involving vertical acceleration, then the other variables in the equation will be vertical displacement, vertical velocity, etc.

Your mistake is that you mixed a vertical velocity and a horizontal distance in the one equation!
 
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