Velocity and distance ratio problem

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The discussion revolves around demonstrating that a smaller block, with three times the velocity of a larger block after a firecracker explosion, will travel nine times farther. The user successfully applied momentum equations to establish the velocity relationship and used Newton's second law to show both blocks accelerate at the same negative rate due to friction. By employing the kinematic equation (Vf)^2 = (Vi)^2 + 2a(Xf-Xi), they derived a distance ratio of 1/9 for the larger block to the smaller block. The calculations and reasoning appear sound, confirming the expected outcome. The thread invites further validation or alternative methods from other participants.
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How do u show, without using calculus, that if something initially has 3 times the velocity of another object, how much farther it will travel than the other?

the exact question is: A wooden block is cut into two pieces, one with three times the mass of the other. A depression is made in both faces of the cut, so that a firecracker can be placed init with the block reassembled. the reassembled block is set on a rough-surfaced tabble, and the fuse is lit. When the firecracker explodes, the two blocks separeate and slide apart. What is the ratio of distances each block travels?

I have found that the velocity of the small block will be 3 times that of the other using momentum equations p=mv

So how do i show that the small block will travel 9 times (right?) farther than the other?
 
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I think i got it actually. I showed that the 2 blocks will accelerate at the same (negative) rate using Newtons 2nd law, and friction (i ignored the initial acceleration from the impulse of the firecracker). then used the equation (Vf)^2 = (Vi)^2 + 2a(Xf-Xi) and did some subs after having determined the velocity of the smaller block will be three times that of the larger one. And ended with with a ratio of 1/9, large block/small block, after doing some canceling. Does it sound like i did this right? how else would other ppl do it?
 
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