Velocity and Gravity Problem. Basic question. NEED HELP

  • Thread starter Thread starter PhysicsScrub
  • Start date Start date
  • Tags Tags
    Gravity Velocity
AI Thread Summary
To throw a baseball into orbit on Deimos and have it return, a speed of approximately 3.334 m/s is required. This calculation uses the formula v^2 = GM/R, where G is the gravitational constant, M is the mass of Deimos, and R is its radius. The diameter of Deimos is about 12.0 km, leading to a radius of 6.0 km for the calculation. A brief exchange highlights a misunderstanding regarding the difference between radius and diameter. Understanding these concepts is crucial for solving orbital mechanics problems.
PhysicsScrub
Messages
5
Reaction score
0
1. Deimos, a moon of Mars, is about 12.0 in diameter, with a mass of 2.00×1015 . Suppose you are stranded alone on Deimos and want to play a one-person game of baseball. You would be the pitcher, and you would be the batter!

With what speed would you have to throw a baseball so that it would go into orbit and return to you so you could hit it?




2. v^2=GM/R



3.v = sqrt(6.67*10^-11*2*10^15/12000)
v = 3.334 m/s

 
Physics news on Phys.org
PhysicsScrub said:
1. Deimos, a moon of Mars, is about 12.0 in diameter, with a mass of 2.00×1015 . Suppose you are stranded alone on Deimos and want to play a one-person game of baseball. You would be the pitcher, and you would be the batter!

With what speed would you have to throw a baseball so that it would go into orbit and return to you so you could hit it?




2. v^2=GM/R



3.v = sqrt(6.67*10^-11*2*10^15/12000)
v = 3.334 m/s
Hi PhysicsScrub, Welcome to Physics Forums.

What's the difference between radius and diameter? :wink:
 
gneill said:
Hi PhysicsScrub, Welcome to Physics Forums.

What's the difference between radius and diameter? :wink:

Facepalm... ahah. thanks dude.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top