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Velocity and Speed question

  1. Feb 10, 2013 #1
    1. The problem statement, all variables and given/known data
    Jack and John are standing 6m apart from each other playing soccer. Jack kicks the ball to John and John kicks it back immediately. Jack kicked the ball with a velocity of 5.40 m/s and after 2.6 s he got the ball back. Suppose there's no deceleration of the ball when it's moving and that we can neglect the time for John to kick the ball. What is the speed of the ball when it's kicked back to Jack?


    2. Relevant equations

    V= D/T

    3. The attempt at a solution
    5.4 m/s = 6 /t = 1.11 seconds
    1.11 + 2.6 = 3.71 seconds total
    3.71 = ( (6/5.4) + (6/v) ) = 2.3

    I'm doing something wrong, because i'm not getting the right answer.
    thanks in advance
     
  2. jcsd
  3. Feb 10, 2013 #2

    Doc Al

    User Avatar

    Staff: Mentor

    1.11 is the time it takes for the ball to reach John. 2.6 is the total time.
     
  4. Feb 10, 2013 #3
    I'm an idiot...

    Thanks
     
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