Velocity Time Graph Clarification and Insight Please

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SUMMARY

The discussion focuses on the interpretation of a velocity-time (v-t) graph, specifically when the slope is changing, indicating varying acceleration. A curved v-t graph signifies that the acceleration is either increasing or decreasing over time. An upward sloping curve indicates increasing average acceleration, while a downward sloping curve indicates decreasing average acceleration. A linear slope on a v-t graph represents uniform acceleration, confirming that a constant slope correlates with constant acceleration.

PREREQUISITES
  • Understanding of basic kinematics principles
  • Familiarity with velocity-time graph interpretation
  • Knowledge of the relationship between slope and acceleration
  • Proficiency in using equations of motion, specifically v=(delta)x/(delta)t and A=(delta)v/(delta)t
NEXT STEPS
  • Study the implications of non-linear motion in physics
  • Learn about graphical analysis of motion in kinematics
  • Explore advanced concepts of acceleration and its types
  • Investigate real-world applications of velocity-time graphs in physics
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Students studying physics, educators teaching kinematics, and anyone interested in understanding motion analysis through velocity-time graphs.

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Homework Statement



What type of motion is occurring when the slope is changing and the graph is therefore curved on a velocity time graph?


Homework Equations



v=(delta)x/(delta)t

A= (delta)v/(delta)t



The Attempt at a Solution



my thought is that when the slope is changing the acceleration is either increasing or decreasing ...

So if I were to have an upward sloping curved v-t graph, this would mean that the average acceleration is increasing with time, while if i were to have a downward sloping v-t graph the average acceleration would be decreasing with time...

and if i had a line (linear) slope on a v-t graph, we would have uniform acceleration...
 
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Yep. The slope of a velocity-time graph is acceleration. So if the function is linear ie slope is constant, then acceleration is constant. It the slope isn't constant you have a changing acceleration.
 

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