Velocity vs Time: Dropped Ball Analysis

Click For Summary

Homework Help Overview

The discussion revolves around analyzing a velocity vs. time graph for a ball that is dropped from a height. Participants explore concepts related to motion under gravity, including the interpretation of slopes in the context of velocity and acceleration.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between slope, velocity, and acceleration, questioning how these relate to the motion of a dropped ball. There are inquiries about the nature of free fall and the effects of initial velocity on the analysis.

Discussion Status

The discussion is active, with participants offering insights into the implications of constant acceleration due to gravity. Some participants have proposed different answers based on their interpretations of the graph, and there is a recognition of the need to clarify the definitions of initial velocity and acceleration.

Contextual Notes

There is an ongoing examination of the assumptions regarding initial conditions, such as whether an object is dropped or thrown, and how these conditions affect the analysis of the graph. Participants are also considering the implications of constant acceleration in their reasoning.

goonking
Messages
434
Reaction score
3

Homework Statement



http://imgur.com/FJzyuSY

Homework Equations

The Attempt at a Solution


since the graph is velocity and time, i believe the slope SHOULD be distance or placement, correct?

and 1 ball is dropped above the ground so I assume the answer is B since it has a line starting above the 0.

and it makes sense since the slopes are curved because acceleration due to gravity will make the slopes curved, is this correct?
 
Physics news on Phys.org
Slope is rise over run. Your rise is velocity, and your run is time. What is velocity / time? That's your slope.
 
tony873004 said:
Slope is rise over run. Your rise is velocity, and your run is time. What is velocity / time? That's your slope.
oooh, the slope is acceleration.
 
if you throw straight down something instead of dropping it, is it still in free fall? is the acceleration greater than the force of gravity?
 
Last edited:
Acceleration near the surface of the Earth is considered constant. Earth will not pull any harder on the object with initial velocity. The only difference between the object dropped and the object thrown straight down is that the object dropped has 0 initial velocity and the object thrown has negative initial velocity. Knowing that should eliminate 3 of your choices.
 
is the answer D? because the slopes are constant so acceleration is constant which is true because force of gravity doesn't change, it will always be -9.8 m/s^2.

but it also doesn't make sense because if a object is dropped from free fall, its initial velocity should be at 0.
 
No the answer is not D. Sure the slopes are constant in D, but they're a constant 0. We know that on Earth they should be a constant -9.8.
There's another graph with constant slopes. (Hint: constant means straight line, whether its horizontal like D, or sloped).
 
ahhh, so the answer is A because the slope is a negative value.
 
Yes! And they both have the same negative slope since gravity accelerates each one equally, and the top one begins with 0 velocity because it was dropped, and the bottom one begins with negative velocity because it was thrown.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
34
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
7
Views
3K