Velocity When a Runner Covers Half a Lap

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The discussion focuses on calculating the average velocity of a runner covering half a lap on a circular track with a diameter of 40 meters. The runner completes the first half-lap in 28.7 seconds. The key to determining average velocity is recognizing that it is the change in displacement divided by the change in time. Since the runner starts and ends at the same point after a full lap, the displacement for half a lap is the straight-line distance across the diameter, which is 40 meters. The average velocity is calculated as 40 m divided by 28.7 s, resulting in approximately 1.4 m/s.
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Homework Statement



A runner covers one lap of a circular track 40.0 in diameter in 63.2 .

If she covered the first half-lap in 28.7 , what were her average velocity for that half-lap?


Homework Equations



We use perimeter of a cirle = 2*3.14*20m to get 125.6

The Attempt at a Solution



I know that if the runner runs around a full lap, he or she will be at 0 velocity. But at half a lap I tried 62.8/28.7 to get 2.188. I am sure that is the speed and not the answer. I know I am making a small mistake.
 
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Hint: Average velocity is the change in displacement (a vector) divided by the change in time. So what's the change of the runners dsplacement, both in magnitude and direction?
 
No ideas? 1?
 
I gave you the hint. Take it from there.
 
the runner ends in the same place he/she starts.
 
dnp33 said:
the runner ends in the same place he/she starts.
After one lap, she does, but not after half a lap.
 
haha.
well apparently i can't read.
 
Got it, 1.4 m/s because displacement is the shortest distance. This would be 40 m / 28.7 s.
 
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