Velocity with air resistance help

AI Thread Summary
The discussion focuses on finding the velocity (V) using the equations V=Vo+AT and A=G-KV. Participants explore how to manipulate the equation V=Vo+(G-KV)T to isolate V. They discuss various algebraic steps, including factoring and rearranging terms, to achieve the desired form. The conversation highlights the importance of understanding the relationship between changing acceleration and velocity. Ultimately, the equation V=(TG+Vo)/(1+TK) is confirmed as a solution, with emphasis on the process of simplification and manipulation.
PHK
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I need to find the velocity with the following information. V=Vo+AT and A=G-KV

so how would i find what V equals from this: V=Vo+(G-KV)T
 
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Thats right. Is there something else to the question too? What velocity do you have to find?
 
theres nothing else to the problem. i plugged in G-KV in for A in the first equation but now i have V=Vo+(G-KV)T. and i want to find velocity, but can't because there is velocity in the equation. so i want to know how to simplify the equation so i get V only on one side.
 
did anyone figure it out yet?
 
PHK said:
did anyone figure it out yet?

V=Vo+(G-KV)T

V = Vo + GT - KVT

V + KVT = Vo + GT

etc...
 
I think this is right:

V=Vo+(G-KV)T = Vo+TG-TKV
V-Vo=TG-TKV
V-Vo+TKV=TG
V+TKV=TG+Vo
V(1+TK)=TG+Vo

V=(TG+Vo)/(1+TK)[EDIT]oops, looks like learningphysics beat me to it.
 
"Replacement by an equal expression" is a procedure that is used a lot.
( like you replaced the "A" by "G-kV" )
"Multiplication, Distributive" ( Phoenix line 1 ) and
its inverse , "Factoring" (Phoenix line 5) are the basis of proportion.
When you add the negative of some term to both sides
(so that term cancels the original term on that side)
and/or divide both sides by the same factor
(so as to "move the factor to the other side")
... there's always more than one path that you can take
notice how Phoenix "undid" in line 4 , what he had done in line 2 ...
it is okay to take more steps, so long as you keep the goal in mind.
 
thanks the equation works. i got one question tho. how did you get from this V+TKV=TG+Vo
to this V(1+TK)=TG+Vo?
 
PHK said:
I need to find the velocity with the following information. V=Vo+AT and A=G-KV

so how would i find what V equals from this: V=Vo+(G-KV)T
Where did you get the equation V = Vo + AT? This equation is derived from calculus for the special case of constant acceleration. In your case, the acceleration is changing with speed, and is therefore not constant.
 
  • #10
PHK said:
thanks the equation works. i got one question tho. how did you get from this V+TKV=TG+Vo
to this V(1+TK)=TG+Vo?

he factored out the V... try multiplying out: V(1+TK)... what do you get?
 
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