Verify Net Force on 810kg Car Accelerating from Rest to 27m/s in 120m

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An 810kg car accelerates from rest to 27m/s over a distance of 120m. The user calculated the acceleration using the formula a = Vf^2 - Vi^2 / 2x, resulting in an acceleration of approximately 3.075 m/s². They then applied Newton's second law, F = MA, to find the net force, calculating it to be around 2460.375 N. The user seeks verification of their calculations and is open to further assistance. Overall, the calculations appear correct based on the provided information.
rkslperez04
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Hey everyone,

Im studying for a test and wanted to verify my problems. I thought I would dabble on the dark side of the textbook and try the even ones too.

Can you verify my answer?

Kelly :)

A 810kg car accelerates from rest to 27m/s in a distance of 120m. That is the magitudeof the aver net force acting on the car?

Here is what I did.

1) step up my list of info:
Vi = 0
Vf = 27 m/s
a =
t =
x = 120 m

2) Figured I needed the F=MA equation

I have the mass so solve for acceleration.

3) a = Vf^2 - Vi^2 / 2x... which is: 27^2 / 2*120 = 3.075 m/s^2

I plugged A into the equation

4) F = (810 kg)(3.0375 m.s^2)
F = 2460.375


? did I get it?
 
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Looks good to me :smile:
 
Great thanks.. got a few more i will post.. I would apperciate a second opinion and a nudge or two... :)
 

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