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savva
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Could anyone please verify with me that I have the right idea in answering the question below.
If you know the initial velocity v0 and the initial and final heights y0 and y, you can use x=x0+v0t+(1/2)at^2 to solve for the time t when the object will be at height y. But the equation is quadratic in t, so you'll get two answers. Physically, why is this?
This occurs because during the motion of an object it has passed through it's initial displacement on 2 occassions. Thus times occur twice.
Homework Statement
If you know the initial velocity v0 and the initial and final heights y0 and y, you can use x=x0+v0t+(1/2)at^2 to solve for the time t when the object will be at height y. But the equation is quadratic in t, so you'll get two answers. Physically, why is this?
The Attempt at a Solution
This occurs because during the motion of an object it has passed through it's initial displacement on 2 occassions. Thus times occur twice.
