The discussion focuses on verifying the vector formula A.B = B.A, which pertains to the scalar product of vectors A and B. The formula is confirmed through the relationship A.B = ABcos(x) and B.A = BAcos(x), highlighting that both expressions yield the same result. It emphasizes that since arithmetic multiplication is commutative, AB equals BA. Thus, the formula holds true for the scalar product of vectors. The conclusion reinforces the correctness of the vector equality based on these mathematical principles.