Engineering Very simple superposition circuit

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The user is analyzing a superposition circuit to determine the current I. They calculated the total resistance as 150 ohms and found the current from one source to be approximately 0.067 A, resulting in 33.5 mA through a specific resistor. For the second source, the current was approximately 0.033 A, yielding 16.5 mA through the same resistor. By summing the currents from both sources, the total current I is concluded to be 50 mA. The calculations appear to be correct based on the superposition principle.
James889
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Hi,

I have didn't have an answer to this, so i need someone to tell me whether my work is correct or not.

This is the circuit:
[PLAIN]http://img251.imageshack.us/img251/4081/circuit1.png

I need to determine the current I.

Remove the first source and calculate the current provided by the other.
[PLAIN]http://img255.imageshack.us/img255/1665/circuit11.png


The total resistance is 150ohm 100 + \frac{100 \cdot 100}{100+100}

I = 10/150 ~0.067A

And the current through the resistor is:

\frac{100}{200} \cdot 0.067 = 33,5mA


Do the same with the other source
[PLAIN]http://img69.imageshack.us/img69/9727/circuit12.png

I = 5/150 ~0.033A
\frac{100}{200} \cdot 0.033 = 16,5mA


So the current I should be 50mA
 
Last edited by a moderator:
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yes correct
 

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