Vf = 0.88 m/s Solving Momentum Question: 82kg Girl & 46kg Boy on Skateboard

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An 82kg girl coasting at 1.8 m/s on a 2.0kg skateboard has a boy weighing 46kg jump on, prompting a momentum calculation. The initial momentum is calculated as 84kg multiplied by 1.8 m/s, while the final momentum involves the combined mass of 130kg. The correct final speed after the boy jumps on is determined to be approximately 0.97 m/s, not the previously calculated 1.163 m/s. There is some uncertainty regarding the textbook answer, but the calculations suggest the final speed should be lower than initially thought. The discussion emphasizes the importance of correctly applying momentum conservation principles.
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Homework Statement


A 82kg girl is coasting along the floor on a large 2.0kg skateboard. If she is moving 1.8 m/s when a 46kg boy jumps on to the same skateboard, what is the speed of the skateboard immediately after the boy jumps on it?


Homework Equations



Sum of Initial Momentum = Sum of Final Momentum

The Attempt at a Solution



This question looked pretty easy.. but I am sure I am doing something wrong... here's what I did so far:
(84kg)(1.8m/s) + (130kg)(0m/s) = (84kg + 130kg)Vf
 
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Sorry.. forgot the last part..
I got vf=0.7065m/s

Im not sure if this is right or not.. it SEEMS like an okay speed.. but I havn't done this type of question before.. so just want to be sure. Thanks!
 
niki4d said:
(84kg)(1.8m/s) + (130kg)(0m/s) = (84kg + 130kg)Vf


You should only be looking at the initial and final momentums of the skateboard (and what ever is on it).

So it starts off with a total mass of 84 kg, going at 1.8 m/s. At the end, It has the mass of a 46 kg boy, so the total mass is 130 kg, and v_1 m/s is what we are trying to find. Equating both sides and making v_1 the subject;

84 kg \cdot 1.8 ms^{-1} = 130 kg \cdot v_1 ms^{-1}

v_1 = \frac{84 \cdot 1.8}{130}

I can already tell that's larger than one, so recheck your answer =]
 
Hmm.. that makes sense.. but the answer to that would be 1.163m/s. The answer is 0.97m/s. I don't know how to get to that..
 
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Well, That is somewhat odd...I think it's an error in the textbook, but it has been a while since I've studied Physics so I recommend you wait for someone who has more knowledge in this area to confirm.
 
unless there are something else in the problem we have not addressed, otherwise I believe Gib Z's correct.
 
Yeah.. more than likely it is.. thanks for the help!
 
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