Vibrations problem - Transverse in a string under tension

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SUMMARY

The discussion focuses on deriving the equation for natural frequencies of a cord under tension, specifically given by the formula tan(wL/c) = -(T/kL)((wL/c)/(1-(w/w_n)^2)). Key parameters include tension T, density p, cross-sectional area S, and the spring constant k. The relationship between natural frequency and wave speed is established through the equations w_n^2 = k/m and c^2 = T/(pS), which are essential for solving the problem. The participants confirm the validity of the equation and clarify the relationship between frequency, wave speed, and wavelength.

PREREQUISITES
  • Understanding of wave mechanics, specifically transverse waves in strings.
  • Familiarity with tension, density, and cross-sectional area in physical systems.
  • Knowledge of natural frequency calculations and spring-mass systems.
  • Basic grasp of trigonometric functions and their applications in physics.
NEXT STEPS
  • Study the derivation of wave equations in strings under tension.
  • Learn about the relationship between tension, density, and wave speed in physical systems.
  • Explore the concept of natural frequencies in spring-mass systems.
  • Investigate the application of trigonometric functions in solving physical problems.
USEFUL FOR

Students and educators in physics, particularly those focusing on wave mechanics and oscillatory systems, as well as engineers working with tensioned materials and spring dynamics.

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Homework Statement


A cord of length L density p and cross-sectional area S is under tension T with the left end fixed and the right end attached to a spring-mass sstem. Show that the equation for the natural frequencies is given by:

tan(wL/c) = -(T/kL)((wL/c)/(1-(w/w_n)^2))


Homework Equations



w_n^2 = k/m and c^2 = T/(pS)

The Attempt at a Solution



I have tried this but I am really having problems starting this problem out, please help
 
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Are you sure that equation is right? The natural frequencies are given very simply by f=v/lambda, where v^2=c^2 = T/(pS) and lambda is a half-integer multiple of the pipe's length.
 
Yes it is Q.2 on the sheet which I have attached.
 

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