Voltage and parallel capacitor distance

AI Thread Summary
Increasing the distance between two parallel capacitors in a circuit does not change the voltage when a battery is connected because the battery maintains a constant voltage output. According to Kirchhoff's Voltage Law, the total voltage around a closed loop must equal zero, which means the voltage across the capacitors remains constant regardless of distance. The equation V = Efield x distance assumes a uniform electric field, but in a circuit with a battery, the voltage is dictated by the battery's output rather than the physical distance between capacitors. This highlights the distinction between theoretical calculations and practical circuit behavior. Understanding these principles clarifies why voltage remains constant in this scenario.
caljuice
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Assuming the long parallel capacitors to be fully charged and no resistance. So if you increase the distance between two capacitors in a circuit the voltage increases between them. But why is it when a battery is connected to the capacitors in the circuit, increasing the distance won't change the voltage between them?

V= Efield x distance so I'd think V would increase. Am I wrong to assume E is the same at both distances?
 
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I don't think you're saying what you mean.

However, the answer is that the battery supplies a constant voltage. Look at Kirchhoff's Voltage Law.
 
I think I'm saying what I mean lol. It doesn't make sense?

Ah Kirchoff rule, I forgot about him. I see the voltage would then have to be equal since Vloop=0. But I still don't see why V= Efield* Distance doesn't apply in this capacitor circuit? Hope that sounds better.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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