Voltage Div. Homework: Find Voltage Drop Across 2K Ohm Resistor

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The discussion focuses on calculating the voltage drop across a 2k ohm resistor using voltage division, with a previous result of 250V from part b concerning a 10k resistor. Participants clarify that the total resistance (R_T) is 5k ohms, which includes a combination of resistors in parallel and series. One contributor points out that the 6kΩ, 18kΩ, and 9kΩ resistors are in parallel, affecting the total resistance calculation. The confusion arises from miscalculating R_T, leading to an incorrect voltage drop estimate. Ultimately, the correct voltage drop across the 2k ohm resistor is confirmed to be 50V.
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Homework Statement


see attached for circuit

from your result from part b, use voltage division to find the voltage drop across the 2k ohm resistor. my result from b was 250V

part b question was voltage drop across 10K resistor

Homework Equations





The Attempt at a Solution


R_T=5k ohms

v=V_2k/V_T = 100v but the answer is 50V?

Thanks
 

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What does R_T stand for?
 
total of the other resistors
 
You must have calculated RT wrong.

I get the book answer.
 
Don't forget the 5kΩ resistor.
 
can you tell me how please, I got 5k for Rt
 
The 6kΩ, 18kΩ, and 9kΩ resistors are all in parallel with each other.

That combination is in series with the 5 kΩ and 2 kΩ resistors.

The above is what I would call RT, judging by the way you used RT.
 
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