Voltage output for ideal diode (solutions wrong?)

[pyroknife]

I'm looking at some solutions for a problem I found. This link is http://www.etcs.ipfw.edu/~lin/MET487/2011-SumII/Lectures/Hw3_Sols-MET487-Sum2011.PDF
It's page 4 problem 3.1.


Okay so V_in is given to be 10cos(2∏t), but their graph for V_in makes no sense to me and consequently, V_out seems wrong as well.

Am I missing something here or is their graph for V_in totally off? The magnitudes are right but their period seems a factor of 2 off.

 

[ehild]

I'm looking at some solutions for a problem I found. This link is http://www.etcs.ipfw.edu/~lin/MET487/2011-SumII/Lectures/Hw3_Sols-MET487-Sum2011.PDF
It's page 4 problem 3.1.


Okay so V_in is given to be 10cos(2∏t), but their graph for V_in makes no sense to me and consequently, V_out seems wrong as well.

Am I missing something here or is their graph for V_in totally off? The magnitudes are right but their period seems a factor of 2 off.

You are right, the period is wrong.

ehild

 

[pyroknife]

You are right, the period is wrong.

ehild

Thanks. Any clue what they were doing by finding frequency? I don't see any point in doing that.

 

[ehild]

The time dependence of an AC voltage is U=Acos(ωt). The input voltage is U=10cos(2pi t). So what is the angular frequency ω? How is it related to the frequency and to the time period?
The scaling in the picture is wrong.

ehild

 

[pyroknife]

Yeah I know that the relationship between angular frequency and frequency is
angularfrequency=2*pi*frequency
and that period=1/frequency.

I just don't understand why they went through the hassle of calculating frequency to draw a simple sinusoidal graph. Frequency was never asked to be calculated, so i didn't see the point in calculating it unless they somehow saw this as an easier way of drawing a simple cosine function.

 

[ehild]

They needed to graph time dependence of the output voltage. (But they did it wrong)
ehild