Voltage Question: Find Voltage Drop with 3.30A Draw

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To find the voltage drop across wires connecting an apparatus 62.3 meters from a 120 V source with a resistance of 0.00600 ohms/m and a current draw of 3.30 A, the total resistance can be calculated by multiplying the resistance per meter by the distance. This results in a total resistance of 0.3738 ohms. The voltage drop is then determined by multiplying the total resistance by the current, yielding a voltage drop of approximately 1.23 V. Understanding the relationship between resistance, current, and voltage drop is essential for solving such electrical problems. Accurate calculations ensure the apparatus operates effectively without significant power loss.
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Voltage question...

Hi; Could somebody please help me with the following question: Suppose you want to run some apparatus that is 62.3 m from an electric outlet. Each of the wires connecting your apparatus to the 120 V source has a resistance per unit length of 0.00600 ohms/m. If your apparatus draws 3.30 A, what will be the voltage drop across the connecting wires? I'm really confused about this question, could someone please help. Thank you.
 
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Jodi said:
Hi; Could somebody please help me with the following question: Suppose you want to run some apparatus that is 62.3 m from an electric outlet. Each of the wires connecting your apparatus to the 120 V source has a resistance per unit length of 0.00600 ohms/m. If your apparatus draws 3.30 A, what will be the voltage drop across the connecting wires? I'm really confused about this question, could someone please help. Thank you.

You know the current and the resistance of each wire. You can calculate the voltage drop across each wire.
 
It's just multiplication. You are given the "voltage drop per meter": that is V/d and are asked to find V for given distance. Have you considered the fact that
(V/d)(d meter)= V?
 
HallsofIvy said:
It's just multiplication. You are given the "voltage drop per meter": that is V/d and are asked to find V for given distance. Have you considered the fact that
(V/d)(d meter)= V?

The problem gives "ohms per meter". That could be converted to a "voltage drop per meter" by multiplying by the current, or you can multiply by the distance to find the total resistance and then multiply by the current to find the voltage drop.
 
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