Voltage regulation under a capacitive load.

AI Thread Summary
Voltage regulation of a transformer becomes negative with a capacitive load because the load reflects power back to the source, leading to an increase in secondary voltage instead of a decrease. This behavior contrasts with resistive loads, which typically cause a drop in voltage. The reactive nature of capacitance means it consumes no power, resulting in oscillations of power. Understanding this phenomenon can be enhanced by studying resonant circuits and simple harmonic oscillators, which illustrate how timing can amplify responses. The interaction between the transformer and capacitive load is crucial for grasping voltage regulation dynamics.
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Homework Statement



Why does the voltage regulation of a transformer become negative when a capacitive load is attached? It causes the voltage across the secondary winding to increases rather than decrease, as would be the case for a resistive load. But why?

Homework Equations



Regulation = (Vn-V)/Vn

where Vn is the voltage at no load

The Attempt at a Solution



As I understand it, the capacitance is obviously reactive and consumes no power, instead it reflects the power back to the source, and this results in an oscillation of power.

I'm probably missing something obvious here, but the negative voltage regulation can't be due to the returning power from the capacitance increasing the voltage?
 
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Yes, you're on the right track with your statement "this results in an oscillation of power". To learn more look into "resonant circuits" and "simple harmonic oscillators". Like pushing a child on a swing, if you do it at just the right time, you can build up a big response.
 
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