Volume by Rotating a Curve: Finding the Solid Between Two Curves

mikhailpavel
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Homework Statement


Hey i have a problem here with volume by cylindrical shells. i wanted to find the given volume of the solid obtained by rotating the region bounded by the curves x=1+(y-2)^2 and x=2 about the x axis.


Homework Equations


we tried to integrating 2 phi f(y) dy with upper limit 3 and lower limit 1.


The Attempt at a Solution


we got the answer 33.5 but i don't think it is the correct one.
immediate help will be appreciable.
 
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You are using cylindrical shells, but your formula is incorrect. A typical shell in this problem has a volume of 2pi*y*(x2 - x1)*dy

x2 is the x-value on the line x = 2, and x1 is the x-value on the parabola. You have graphed the region being revolved, right?
 
can u tell me if my upper and lower limits are right because still i am not getting the right answer..i think!
 
Yes, the two curves intersect at (2, 1) and (2, 3) so y ranges between 1 and 3.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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