Volume, pressure and final temperature

In summary, the air has an initial temperature of 500°C and pressure 0.8 MPa. It is expanded to a final volume of 90 liters at a final temperature of 600°C.
  • #1
Ben_Walker1978
113
6

Homework Statement



a) A mass of 0.12 kg of air has an initial temperature of 500°C and pressure 0.8 MPa. If the air is expanded according to the law pV1.2 = c to a final volume of 90 litres, determine
i) its initial volume,

ii) its final pressure,

iii) its final temperature.
For air, take R = 287 Jkg¯¹ K¯¹.

Homework Equations


pV1.2 = c
pV = nRT
n = pxV / RxT

The Attempt at a Solution



Can anyone point me in the right direction?
As i have no clue how to complete this.
Thanks.
 
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  • #2
We aren't allowed to give the answer unless you show us your work attempting a solution. "No clue" is not enough.
 
  • #3
Hello.

i have done a bit of working out.

I converted celcius to kelvin. Which is 773.15

i think 1.2 is how dry the air is?

n = 0.8 x 90 / 287 x 773.15 = 193.96

So n = 193.96

So i have all the information for the equations.

Is is just pV1.2 = c
 
  • #4
Ben_Walker1978 said:
n = 0.8 x 90 / 287 x 773.15 = 193.96
This will not work. You have mixed the initial pressure and final volume.

Part one asks for the initial volume. How could you use the ideal gas law and the given relation ##1.2pV=c## to find this?
 
Last edited:
  • #5
How many gram moles of air does 0.12 kg represent?
 
Last edited:
  • #6
i thought i worked this out in my previous post.

The molar mass of air is 29g/mol
 
  • #7
Ben_Walker1978 said:
The molar mass of air is 29g/mol
So what is ##n## in this case?
 
  • #8
Ben_Walker1978 said:
i thought i worked this out in my previous post.

The molar mass of air is 29g/mol
I don't see it there. If the molar mass of air is 29 g/mol, how many gram moles of air does 0.12 kg represent? It is definitely not 194.
 
  • #9
3.48?
 
  • #10
Ben_Walker1978 said:
3.48?
Please show how you arrived at this number?
 
  • #11
I have worked it out i think.

0.12kg / 0.029kg/mol = 4.1379

Is this correct?
 
  • #12
Ben_Walker1978 said:
I have worked it out i think.

0.12kg / 0.029kg/mol = 4.1379

Is this correct?
Yes. Now you know the number of moles, the initial temperature, and the initial pressure. So, from the ideal gas law, what is the initial volume ##V_i##?
 

FAQ: Volume, pressure and final temperature

1. What is the relationship between volume and pressure?

The relationship between volume and pressure is known as Boyle's law, which states that at a constant temperature, the volume of a gas is inversely proportional to its pressure. This means that as pressure increases, volume decreases, and vice versa.

2. How does temperature affect the volume of a gas?

According to Charles's law, at a constant pressure, the volume of a gas is directly proportional to its temperature. This means that as temperature increases, volume also increases, and as temperature decreases, volume decreases.

3. What is the ideal gas law?

The ideal gas law is a mathematical equation that describes the relationship between the pressure, volume, temperature, and amount of a gas. It is written as PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

4. How do changes in pressure and temperature affect the final temperature of a gas?

According to the combined gas law, the final temperature of a gas is affected by both its initial temperature and pressure. As pressure increases, the temperature also increases, and as pressure decreases, the temperature decreases. Similarly, as temperature increases, pressure also increases, and as temperature decreases, pressure decreases.

5. What is the relationship between volume, pressure, and temperature in a gas?

The relationship between volume, pressure, and temperature in a gas is described by the ideal gas law. This law states that at a constant number of moles, the product of pressure and volume is directly proportional to the temperature of the gas in Kelvin. This means that as two variables increase or decrease, the third variable will also increase or decrease proportionally.

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