Walk a 3-sphere w/Hopf Fibration: Parameterization

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SUMMARY

The discussion focuses on parameterizing a path on a three-sphere (S3) using the Hopf fibration, which maps S3 to a two-sphere (S2). By selecting a starting point on S3 and moving infinitesimally perpendicular to the fibers, one can derive a path that corresponds to a great circle on S3. The key to this parameterization lies in the relationship between the chosen point on S3 and its image on S2, allowing for a unique reconstruction of the path on S3 through the mapping p: S3 → S2.

PREREQUISITES
  • Understanding of three-sphere (S3) and two-sphere (S2) topology
  • Familiarity with the concept of Hopf fibration
  • Knowledge of differentiable paths and tangent vectors
  • Basic grasp of parameterization in mathematical contexts
NEXT STEPS
  • Explore the properties of the Hopf fibration in detail
  • Study the mathematical implications of parameterizing paths on S3
  • Investigate the relationship between tangent vectors and fibers in differential geometry
  • Learn about applications of S3 and S2 in physics and topology
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Mathematicians, physicists, and students interested in differential geometry, specifically those studying the topology of spheres and the applications of the Hopf fibration.

Hornbein
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Consider a three-sphere with a Hopf fibration. Choose a point on one fiber. Move an infinitesimal distance ds perpendicular to that fiber to reach a point on another fiber. Repeat ad infinitum. What is a parameterization of the resulting path?
 
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You would end up walking in a great circle. Parametrize that however you like.
 
All distances are either positive or zero; there are no infinitesimal distances.

But if you are asking about a differentiable path on the 3-sphere S3 whose tangent vectors are always perpendicular to the fibres of the Hopf fibration . . .

(and note that the Hopf fibration may be thought of as a specific mapping

p: S3 → S2

from the 3-sphere to the 2-sphere)

. . . then your path is equivalent to specifying a starting point x on S3, and also a path on S2, beginning at p(x), that represents the path on S3 after it has been pushed down to S2 by applying the mapping p to each point of your path.

In other words, given the starting point x on S3, and the image under p of your path in S2, that is all you need to know in order to uniquely reconstruct your path on S3.
 

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