Washer Hanging from Box Moving Down a Ramp

  • Thread starter Thread starter Gwozdzilla
  • Start date Start date
  • Tags Tags
    Box Ramp
AI Thread Summary
A steel washer is suspended inside a shipping crate sliding down a 37° ramp, with the crate's mass at 180 kg and an occupant's mass at 55 kg. The washer remains at rest relative to the crate, making a 68° angle with the top of the crate. The discussion focuses on deriving the equations for the forces acting on the washer to find the coefficient of kinetic friction between the ramp and the crate. The equations involve analyzing the tension in the string and the gravitational forces acting on the washer. Clarification is sought on the origin of the force equations for the washer, indicating a need for deeper understanding of the physics involved.
Gwozdzilla
Messages
81
Reaction score
0

Homework Statement


A steel washer is suspended inside an empty shipping crate from a light string attached to th top of the crate. The crate slides down a long ramp that is inclined at an angle of 37° above the horizontal. The crate has mass 180kg. You are sitting inside (with a flashlight); your mass is 55kg. As the crate is sliding down the ramp, you find the washer is at rest with respect to the crate hen the string makes an angle of 68° with the top of the crate. What is the oefficient of kinetic friction between the ramp and the crate?


Homework Equations


ƩF=ma
fk=μn


The Attempt at a Solution


Let mc = mass of crate
and my = mass of you
and m = mass of washer
ƩFcrate system = (mc + my)a = (mc + my)gsin(37) - μ(mc + my)cos(37)

Canceling out the combined mass and solving for μ gives:

μ = [gsin(37) - a]/[gcos(37)]

Apparently...
Let T = tension in string
ƩFy-washer = ma1 = Tsin(22) -mgsin(37)
and
ƩFx-washer = ma2 = Tcos(22) -mgcos(37)

And a2 = 0 allowing for these two equations to be rearranged and then divided by each other giving...
tan(22) = [gsin(37) - a]/[gcos(37)]

My actual question:

Where are the ƩFwasher equations coming from? I have the attached picture to help, but I still don't understand.
 

Attachments

  • image.jpg
    image.jpg
    5.4 KB · Views: 630
Physics news on Phys.org
Where are the ƩFwasher equations coming from? I have the attached picture to help, but I still don't understand.
Free body diagram for the washer.
So you didn't derive the equations yourself then?

You can also look at it from the POV of you - if the crate were stationary on the slope, what angle would the washer make to the ceiling?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top