Understanding and Solving a Box Plot Math Problem

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Wat does this mean? HELP!

Ok so I've been givin this question and it makes no sence.

A class of 12 students sat for a Maths test and achieved a set of results that matched the box plot shown below. The class mean was 16. Produce a set of results that satisfies both conditions.B](see Diagram in the attachment).

What does this question mean?

What is this question asking for??

And how do you do it??

Can anyone help me do it or show me how to do it?
 

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You are asked to give 12 scores that all lie between 10 and 20 (because those are the upper and lower bounds of the box) and have an average value of 16.
 


so how do i do that?
 


By thinking! You have all the information you need.
 


could u pleas start me off and point me in the rite direction??
 


xX-Cyanide-Xx said:
could u pleas start me off and point me in the rite direction??
First it is against our rules to post in text speak.. Use standard English.

Make an effort.

Show an effort.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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