- #1
asura
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Homework Statement
Water falls at the rate of 250 g/s from a height of 60 m into a 780 g bucket on a scale (without splashing). If the bucket is originally empty, what does the scale read after 2 s?
Homework Equations
p=mv
F[tex]\Delta[/tex]t=[tex]\Delta[/tex]p
The Attempt at a Solution
So I assumed that the water was already beginning to fill the bucket at t=0, since it can't reach the bucket in 2s.
First I found the velocity of the water right before it fills the bucket...
vf2=vi2+2ax
vf2= 2(9.81 m/s2)(60m)
vf= 34.3 m/s
Then I used the impulse momentum theorem...
F[tex]\Delta[/tex]t=[tex]\Delta[/tex]p
F( 2 s) = .500 kg( 0 - 34.3 m/s)
F = 8.58 N
Weight of the bucket is mg, which is 7.65 N...
so 8.58 + 7.65 is 16.2 N
im not sure about this though... can someone double check my work, I only have one try left
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