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Water flow question

  1. Mar 10, 2008 #1
    Thanks everyone for the warm welcome! Having said that, please forgive me if I'm being ignorant or unintentionally lazy.

    I was also unsure where to put this question. Again, my apologies if it's in the wrong area. Ok! On to my questions. And by all means point me to some reading material instead of answering if you want to! I'm not above educating myself! :wink:

    Scenario (I will try to provide as much information as I can think of):

    Temperature: 5 degrees Celsius
    Elevation: 1 meter AMSL
    Atmospheric Pressure: 29.9
    Humidity: 50%

    Container properties:
    1 cubic meter @ 10 cm thickness
    Temperature: 5 degrees Celsius
    Water Drain: One 2.5 cm opening placed in the center of one of the cube walls (facing 'down').
    Air Drain: One 2.5 cm opening placed directly opposite of the water drain (facing 'up')

    Water properties:
    Quantity: 1000 liters
    Temperature: 5 degrees Celsius

    The Question(s)
    At what rate in centimeters per second will the water flow through the drain opening? Will the flow rate changes as water is emptied from the container? At what rate will the change be?

    How much work would be required to pump the water back into the cube assuming the water emptied into another container shaped like the one mentioned above? The cube in which the water empties into is .5 meters to the right and .5 meters below the container mentioned above. Assume that a hose 2.5 cm in diameter is attached to the water drain which has a 2.5 cm 'nozzle' on it.

    I hope I provided enough information and thanks for pointing me in the right direction!


    -Arkham Angel-
  2. jcsd
  3. Mar 10, 2008 #2
    Err.. are these types of questions too much, too elementary or? Anyone point me in the right direction at least?


    -Arkham Angel-
  4. Mar 10, 2008 #3
    Yes, go to the forum you want to post in. Look for a button called New Thread. Click that button and you're set.
  5. Mar 10, 2008 #4
    If I could only get the formula or a site that could help explain it would be great. No need to do it for me. Teach me to fish. :-)
  6. Mar 10, 2008 #5
    Any formula or site provided would be a great help!


    -Arkham Angel-
  7. Mar 10, 2008 #6


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    Staff Emeritus
    Science Advisor
    Gold Member

    This link should give you the equation you need. Sorry for the useless noise posted before.
  8. Mar 10, 2008 #7

    I probably sound like a sod, but that is a lot to take in! I see there are a lot of convenient links to explain things in detail though. Wiki is nice.

    Thanks for the link. I don't understand some of the material presented in Bernoulli's principle; rather, I don't understand why (yet) :biggrin:.

    So the voyage begins! I'll post what I discover when I figure it all out.
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