Water pressure vs. area of an object

AI Thread Summary
The discussion focuses on understanding the relationship between water pressure and the area of an object submerged at great depths, specifically a solid copper ball. The pressure at the ocean's bottom is calculated using the equation P=Po+pgh, but the challenge lies in correlating the initial and final pressures with the object's area. The concept of volume elasticity is highlighted, suggesting that the bulk modulus of copper is crucial for solving the problem. Participants are encouraged to refer to textbooks for tables on the bulk modulus of copper and its alloys to aid in their calculations. The inquiry emphasizes the need for a deeper understanding of material properties under pressure.
ebeck1
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I've been looking at this question for about 1 hour now, and cannot figure out the relationship between the distance an object is at the bottom of the ocean vs. its area... The question is:
A solid copper ball with a diameter of 3.20 m at sea level is placed at the bottom of the ocean, at a depth of 7.0 km. If the density of the seawater is 1030 kg/m3, how much does the diameter of the ball decrease when it reaches bottom?

I used the equation P=Po+pgh to solve for the pressure at the bottom of the ocean but cannot find a relation of initial pressure and initial are to final pressure and final area...
 
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This problem is obviously about volume elasticity, don't they give you the bulk modulus? look for tables in your textbook about bulk modulus of copper and its alloys.
 
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