Wave function of a simple harmonic oscillator

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SUMMARY

The discussion centers on the ground state wave function of a one-dimensional simple harmonic oscillator, represented as \varphi_0(x) \propto e^(-x^2/x_0^2). Participants analyze the probability of the system being in the ground state when the wave function is given as \phi \propto e^(-x^2/y^2). The key equation used is dP=|\varphi_0|^2 dx, with references to Peebles' textbook for clarification on the relationship between the wave functions. The integral approach to determine the probability based on energy measurements is also explored.

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically wave functions.
  • Familiarity with the mathematical representation of the simple harmonic oscillator.
  • Knowledge of probability density functions in quantum mechanics.
  • Experience with integration techniques in calculus.
NEXT STEPS
  • Study the derivation of the wave function for the simple harmonic oscillator in quantum mechanics.
  • Learn about probability density functions and their applications in quantum systems.
  • Explore the concept of energy eigenstates and their significance in quantum mechanics.
  • Investigate the implications of measuring energy in quantum systems and how it affects wave function collapse.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those focusing on wave functions and harmonic oscillators, as well as educators teaching these concepts in physics courses.

noblegas
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Homework Statement


The ground state wave function of a one-dimensional simple harmonic oscillator is

\varphi_0(x) \propto e^(-x^2/x_0^2), where x_0 is a constant. Given that the wave function of this system at a fixed instant of time is \phi\phi \propto e^(-x^2/y^2) where y is another constant., find the probability, that if the energy is measured , the system will be in the ground state


Homework Equations





The Attempt at a Solution



dP=|\varphi_0|^2 dx

According to my book(Peebles) , =|\varphi_0|^2=|\phi_0|^2;, so therefore dP=|\phi_0|^2 dx?
 
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anyone still not understand my question?
 
hello noble,
i'm wondering if you take the integral of your state function from 0 to infinity then divide that result the integral of your ground state function from 0-infinity will you get a function dependent on energy, whereas you could use an energy sample at any time to give the probability?
 

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