# Wave Length that gives minimum velocity?

• 01010011
Can somebody please help? :cry:In summary, the answer to the homework question is that the length of the wave that gives the minimum velocity is 1/KU.f

## Homework Statement

The velocity of a wave of length L in deep water is v = K square root of (L/C + C/L)
where K and C are known positive constants. What is the length of the wave that gives the minimum velocity?

## Homework Equations

Possibly a(t) = v'(t) = s"(t)

## The Attempt at a Solution

I don't know how to work the question but here is my best guess...
Can I just cancel L with L and C with C (inside the square root) and be left with v = K.
Next, to find the length, can I just find the antiderivative of the velocity, like this: v(t) = Kt + C.

How do I workout this question?

Hi 01010011! Welcome to PF!

The question is asking for the minimum of (L/C + C/L), where C is a constant.

Hi 01010011! Welcome to PF!

The question is asking for the minimum of (L/C + C/L), where C is a constant.

Thanks for the welcome. Well I was thinking the answer was 0 because the Ls and Cs cancel out each other, but I am not sure

They don't cancel (why do you think they would? )

Try differentiating.

They don't cancel (why do you think they would? )

Try differentiating.

Differentiating v = K square root of (L/C + C/L)? I thought I could just cancel the Ls and Cs. Here is another attempt:

v = k square root (L/C + C/L)

v(t) = s'(t)

v(t) = k square root [(L*C^-1) + (C*L^-1)] + C

v(t) = k * [(L*C^-1) + (C*L^-1)] ^ (1/2) + C

s(t) = k * {[(L*C^-1) + (C*L^-1)] ^ (3/2)} / 3/2 + C + D

This looks like madness. I am sure this is not correct.
What steps (and why) should I take to answer questions like this?

Hi 01010011! Welcome to PF!

The question is asking for the minimum of (L/C + C/L), where C is a constant.

Right, since C is a constant, the smallest value C can be is 0, So...

Differentiating v = K square root of (L/C + C/L)? I thought I could just cancel the Ls and Cs. Here is another attempt:

v = k square root (L/C + C/L)

v(t) = s'(t)

v(t) = k square root [(L*C^-1) + (C*L^-1)] + C

v(t) = k * [(L*C^-1) + (C*L^-1)] ^ (1/2) + C

s(t) = k * {[(L*C^-1) + (C*L^-1)] ^ (3/2)} / 3/2 + C + D

This looks like madness. I am sure this is not correct.
What steps (and why) should I take to answer questions like this?

Nooo, this is a mess.

i] s has nothing to do with it, the fact that v is a velocity has nothing to do with it, all you have to do is find the minimum of (L/C + C/L), where C is a constant

ii] why are you trying to minimise the square-root? the square-root is a minimum if and only if the whole thing is a minimum, so minimise the whole thing, it's easier!

iii] you haven't used the chain rule at all … look it up in your book

Right, since C is a constant, the smallest value C can be is 0, So...

erm … that doesn't even make sense, does it?

get some sleep! :zzz:​

Nooo, this is a mess.

i] s has nothing to do with it, the fact that v is a velocity has nothing to do with it, all you have to do is find the minimum of (L/C + C/L), where C is a constant

ii] why are you trying to minimise the square-root? the square-root is a minimum if and only if the whole thing is a minimum, so minimise the whole thing, it's easier!

iii] you haven't used the chain rule at all … look it up in your book

erm … that doesn't even make sense, does it?

get some sleep! :zzz:​

Ok, I got some much needed sleep lol!

Alright, let me try again:

v = K square root of (L/C + C/L)
dy/dx?
Let U = square root of (L/C + C/L)
V = KU
V = 1KU^(1-1)
V = K

hmmm...