Wave on a string meeting a boundary between areas of different densities

Click For Summary

Homework Help Overview

The problem involves analyzing a wave on a string that encounters a boundary between two areas of different densities. The original poster is seeking assistance with understanding how to approach this type of question, particularly in the context of normal modes and wave equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Some participants suggest solving the wave equation separately for each region and ensuring continuity at the boundary. The original poster expresses confusion about the method of solving the wave equation and questions the implications of their calculations. Others note relationships between the amplitudes of the incident, reflected, and transmitted waves, but the original poster struggles to connect these to a solution.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to the problem. Some guidance has been offered regarding the separation of the wave equation, but the original poster continues to seek clarity on the reasoning behind their calculations and how to progress towards a solution.

Contextual Notes

The original poster indicates they are behind on the topic and are preparing for exams, which may influence their understanding and approach to the problem. There is also mention of specific conditions regarding wave continuity and amplitude relationships that are under consideration.

99wattr89
Messages
20
Reaction score
0
This is the problem I'm working on: http://i.imgur.com/PBMFG.png

I'm very behind with normal modes and waves, and I need to figure out how to do this sort of question in time for my exams, so I'm hoping that you guys will be able to help me see how this can be answered.

I've answered the first part, deriving he wave equation, but for the second part I'm feeling very lost. Can someone give me a hint or nudge in the right direction for how to get started with it?
 
Physics news on Phys.org
Do it as two separate problems. Solve the wave equation for x< 0 with "X" amplitude at 0, for x> 0 with "X" amplitude at 0, then determine "X" so the function is continuous at x= 0.
 
HallsofIvy said:
Do it as two separate problems. Solve the wave equation for x< 0 with "X" amplitude at 0, for x> 0 with "X" amplitude at 0, then determine "X" so the function is continuous at x= 0.

Thank you for your reply!

I think I get the idea there, but unfortunately I'm not having much success doing it.

As I understand it, solving the wave equation means solving ∂2y/∂x∂t = 0

(I don't understand why you do that though. Am I wrong in thinking that's the way you solve the wave equation?)

To solve that, I differentiated y wrt x then t, to get ∂2y/∂x∂t = k1wAei(wt-k1x)

So then k1wAei(wt-k1x) = 0

But that would just mean that either A = 0 (which I'm pretty sure just means that there is no wave at all) or that w = 0 (which I think would mean that the wave doesn't move) or k1 = 0 (which I think would mean that the wavelength was infinite and so the wave would effectively be straight line). None of those possibilities seem like anything approaching a solution, so I think I'm doing this wrong.
 
I've been trying other things, but it still doesn't work.

I know that the amplitude of the reflected and incident waves added will equal the amplitude of the transmitted wave, and that dy/dx at 0 will also be equal for the sum of the incident and reflected waves, and the transmitted wave. But all that gives me is;

A +Areflected = Atransmitted

and

k1(A +Ar) = k2At

How can I get from this get to the answer?
 
Can anyone help me with this?
 

Similar threads

Replies
3
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 5 ·
Replies
5
Views
27K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K