Calculating Wave Velocity & Wavelength

AI Thread Summary
A sound wave with a velocity of 600 m/s and a wavelength of 3 m has a frequency of 200 Hz, leading to a time of 0.0025 seconds for a molecule to return to its normal position. In a separate problem, the velocity of transverse waves on a string is 200 m/s with a frequency of 500 Hz, resulting in a wavelength of 0.4 m. The distance between nodes in standing waves is half the wavelength, which is 0.2 m. The discussion clarifies that the length of the string (L) is not needed to determine the distance between nodes, as the frequency and wave speed provide sufficient information. Understanding these relationships is crucial for solving wave-related problems effectively.
timtng
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A sound wave of velocity 600 m/s has a wavelength of 3 m. At a certain instant one of the molecules of the medium is at its normal position. How long will it be before this same molecule is again at its normal position?

v=fλ, f=v/λ =(600m/s)/3m = 200Hz
T=1/f=1/200=.005s

t=T/2 = .0025s Is this answer correct?

Thanks
 
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Another problem of the same sort.

Standing waves are produced on a string for which the velocity of transverse waves is 200 m/s. The frequency of vibration is 500 Hz. How far apart are the nodes?

I can only find λ, λ=v/f=200/500=.4m

I don't know how to finish the rest of the problem
 
So the answer should be λ/2?
 
shouldn't the answer be: L-λ/2
 
I figured since they ask how far apart are the nodes, L has to be a contributing factor.
 
I figured since they ask how far apart are the nodes, L has to be a contributing factor.

Did you notice that there was no "L" given in the problem?

We were given, instead, the frequency.

If you were given the wavespeed (determined by the mass and tension of the string) and length, then you could find the frequency. Here, that's not necessary.
 
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